General inclusion: K_f and $\pi\alpha\gamma_m$ arbitrary

Making the same approximations as in the previous case for $\gamma_m$,but making no assumption about the relative size of K_f and the aspect ratio, we find that DEM gives

(K^*-K_fK_m-K_f) (K_mK^*)^11+b = (1-)^11+b,   which can be rewritten in the form

(1K_f-1K^*) (K^*K_m)^b1+b = (1K_f-1K_m)(1-)^11+b.   It is now easy to check that (DEMKr32) reduces to (DEMKr11) when $b \to 0$ and that (DEMKr32) reduces to (DEMKr21) when $K_f \to 0$.