It is easy to understand that the inertial coefficients
appearing in the kinetic energy T must depend on the densities of
solid and fluid constituents
and
, and also on
the volume fractions v(1), v(2) and
porosities
,
of the
matrix material and fractures, respectively. The total porosity is
given by
and the volume fraction
occupied by the solid material is therefore
.
For a single porosity material, there are only three inertial coefficients and the kinetic energy can be written as
2T = B<>u & B<>U
¯_11 & ¯_12
¯_12 & ¯_22
B<>u B<>U ,
where
is the velocity of the only fluid present.
Then, it is easy to see that, if
,the total inertia
must
equal the total inertia present in the system
. Furthermore, Biot (1956) has shown that
and that
. These three equations are not
linearly independent and therefore do not determine the three coefficients.
So we make the additional assumption that
, where
(Note: This
without
subscripts should not be confused with the stress tensor introduced
earlier in the paper.)
was termed the structure factor by Biot (1956), but has more recently
been termed the electrical tortuosity
(Brown, 1980; Johnson et al., 1982),
since
, where F is the electrical formation factor.
Berryman (1980) has shown that
= 1 + r(1 - 1),
follows from interpreting the coefficient
as
resulting from the
solid density plus the induced mass due to the oscillation of
the solid in the surrounding fluid. Then,
, where r is a factor
dependent on microgeometry that is expected to lie in the range
, with
for spherical grains.
For example, if
and r = 0.5, equation (tau)
implies
, which is a typical value for tortuosity of sandstones.
For double porosity, the kinetic energy may be written as
2T = B<>u & B<>U^(1) & B<>U^(2)
_11 & _12 & _13
_12 & _22 & _23
_13 & _23 & _33
B<>u B<>U^(1) B<>U^(2) .
We now consider some limiting cases: First, suppose that all the
solid and fluid material moves in unison. Then, in complete analogy
to the single porosity case, we have the result that
must equal the total inertia of the system
.Next, if we suppose that the two fluids can be made to move in unison,
but independently of the solid, then we can take
, and telescope
the expression for the kinetic energy to
2T = B<>u & B<>U _11 & (_12+_13) (_12+_13) & (_22+2_23+_33) B<>u B<>U . We can now relate the matrix elements in (allfluidcase) directly to the barred matrix elements appearing in (singleinertia), which then gives us three equations for our six unknowns. Again these three equations are not linearly independent, so we still need four more equations.
Next we consider the possibility that the fracture fluid can oscillate
independently of the solid and the matrix fluid, and furthermore that
the matrix fluid velocity is locked to that of the solid so that
. For this case, the kinetic energy
telescopes in a different way to
2T = B<>u & B<>U^(2) (_11+2_12+_22) & (_13+_23) (_13+_23) & _33 B<>u B<>U^(2) . This equation is also of the form (singleinertia), but we must be careful to account properly for the parts of the system included in the matrix elements. Now we treat the solid and matrix fluid as a single unit, so
_11 + 2_12 + _22 = (1-)_s + (1-v^(2))^(1)_f + (^(2)-1)v^(2)^(2)_f,
_13 + _23 = - (^(2)-1)v^(2)^(2)_f, and
_33 = ^(2)v^(2)^(2)_f,
where
is the tortuosity of fracture porosity alone and
v(2) is the volume fraction of the fractures in the system.
Finally, we consider the possibility that the matrix fluid can oscillate
independently of the solid and the fracture fluid, and furthermore that
the fracture fluid velocity is locked to that of the solid so that
. The kinetic energy
telescopes in a very similar way to the previous case with the result
2T = B<>u & B<>U^(1) (_11+2_13+_33) & (_12+_23) (_12+_23) & _22 B<>u B<>U^(1) . We imagine that this thought experiment amounts to analyzing the matrix material alone without fractures being present. The equations resulting from this identification are completely analogous to those in (firstfrac)-(thirdfrac), so we will not show them explicitly here.
We now have nine equations in the six unknowns and six of these are linearly independent, so the system can be solved. The result of this analysis is that the off-diagonal terms are given by
2_12/_f = (^(2)-1)v^(2)^(2) - (^(1)-1)(1-v^(2))^(1) - (-1),
2_13/_f = (^(1)-1)(1-v^(2))^(1) - (^(2)-1)v^(2)^(2) - (-1), and
2_23/_f = (-1)- (^(1)-1)(1-v^(2))^(1) - (^(2)-1)v^(2)^(2). The diagonal terms are given by
_22 = ^(1)(1-v^(2))^(1)_f,
and
is given by (thirdfrac).
Estimates of the three tortuosities
,
, and
may be obtained using (tau), or
direct measurements may be made using electrical methods
as advocated by Brown (1980) and Johnson et al. (1982).
Appendix A explains one method of estimating
for the whole
medium when the constituent tortuosities and volume fractions are known.