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FOURIER TRANSFORM

We first examine the two ways to visualize polynomial multiplication. The two ways lead us to the most basic principle of Fourier analysis that

A product in the Fourier domain is a convolution in the physical domain

Look what happens to the coefficients when we multiply polynomials.
      \begin{eqnarray}
X(Z)\, B(Z) &\quad =\quad& Y(Z)
\\ (x_0 + x_1 Z + x_2 Z^2 + \cd...
 ...0 + b_1 Z + b_2 Z^2) &\quad =\quad&
y_0 + y_1 Z + y_2 Z^2 + \cdots\end{eqnarray} (1)
(2)
Identifying coefficients of successive powers of Z, we get
   \begin{eqnarray}
y_0 &\quad =\quad& x_0 b_0 \nonumber \\ y_1 &\quad =\quad& x_1 ...
 ... \\  &\quad =\quad& \cdots\cdots\cdots\cdots\cdots\cdots \nonumber\end{eqnarray}
(3)
In matrix form this looks like  
 \begin{displaymath}
\left[ 
\begin{array}
{c}
 y_0 \\  
 y_1 \\  
 y_2 \\  
 y_3...
 ...
\begin{array}
{c}
 b_0 \\  
 b_1 \\  
 b_2 \end{array} \right]\end{displaymath} (4)
The following equation, called the ``convolution equation,'' carries the spirit of the group shown in (3)  
 \begin{displaymath}
y_k \quad =\quad\sum_{i = 0} x_{k - i} b_i\end{displaymath} (5)

The second way to visualize polynomial multiplication is simpler. Above we did not think of Z as a numerical value. Instead we thought of it as ``a unit delay operator''. Now we think of the product X(Z) B(Z) = Y(Z) numerically. For all possible numerical values of Z, each value Y is determined from the product of the two numbers X and B. Instead of considering all possible numerical values we limit ourselves to all values of unit magnitude $Z=e^{i\omega}$ for all real values of $\omega$.This is Fourier analysis, a topic we consider next.



 
next up previous print clean
Next: FT as an invertible Up: Waves and Fourier sums Previous: Waves and Fourier sums
Stanford Exploration Project
12/26/2000