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The Velocity Independent DMO Equation

 In the early 1980's G. H. F. Gardner and colleagues at the University of Houston showed that it was possible to DMO-correct recorded data in a velocity-independent manner. The fundamental basis for Gardner's method for velocity-independent DMO is the recognition that the double-square-root equation can be converted into a single-square-root equation by a radial-plane-diffraction process. After application of DMO, a second diffraction process, which takes place on constant time-slices completes the prestack migration step.

Consider a constant velocity medium with velocity v. With reference to Figure [*], the double-square root (DSR) equation is:  
 \begin{displaymath}
T = \sqrt{T_0^2 + \frac{(m - m_0 + h)^2}{v^2}} + \sqrt{T_0^2 + \frac{(m - m_0 - h)^2}{v^2}}.\end{displaymath} (1)
Here m is the midpoint between source S and receiver R, m0 is the arbitrary location of a fixed scatter point, h is the half-offset, T0 is the one-way zero-offset traveltime from the normal to the constant-time ellipse at (x = (m - m0),y) to b, and T is the time required to traverse the path SPR. Note that in this case, both m0 and m are referenced to the same fixed origin while x = m - m0 is relative to m.

 
Fig1
Fig1
Figure 1
Depth section showing constant-time ellipse for the DSR equation.
view

The ellipse in Figure [*] is the locus of all points (x,y) for which T is constant. It will be convenient to write (1) in the form:

 
 \begin{displaymath}
T = \sqrt{T_0^2 + \frac{(x + h)^2}{v^2}} + \sqrt{T_0^2 + \frac{(x - h)^2}{v^2}}.\end{displaymath} (2)

Following Forel and Gardner (1988), let  
 \begin{displaymath}
A = \frac{vT}{2},\end{displaymath} (3)
and  
 \begin{displaymath}
B = \sqrt{(A^2 - h^2)}.\end{displaymath} (4)
Then  
 \begin{displaymath}
\frac{x^2}{A^2} + \frac{y^2}{B^2} = 1,\end{displaymath} (5)
 
 \begin{displaymath}
b = \frac{4xh^2}{v^2T^2},\end{displaymath} (6)
and the distance from b to P satisfies  
 \begin{displaymath}
d^2 = B^2(1 - \frac{b^2}{h^2}).\end{displaymath} (7)
Since  
 \begin{displaymath}
d^2 = \frac{v^2T_0^2}{4} = (\frac{v^2T^2}{4} - h^2)(1 - \frac{b^2}{h^2}),\end{displaymath} (8)
one has  
 \begin{displaymath}
T_0^2 = (1 - \frac{b^2}{h^2})T^2 - \frac{4h^2}{v^2}(1 - \frac{b^2}{h^2})\end{displaymath} (9)
This is the basic result from which DMO will be derived.


previous up next print clean
Next: Velocity-Independent DMO Up: Bednar: EOM vs. DMO-PSI Previous: Introduction
Stanford Exploration Project
10/10/1997